12x^2-63x^2+36=0

Solution for 12x^2-63x^2+36=0 equation:

12x^2-63x^2+36=0

We add all the numbers together, and all the variables

-51x^2+36=0

a = -51; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·(-51)·36
Δ = 7344
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{7344}=\sqrt{144*51}=\sqrt{144}*\sqrt{51}=12\sqrt{51}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12\sqrt{51}}{2*-51}=\frac{0-12\sqrt{51}}{-102}
=-\frac{12\sqrt{51}}{-102}
=-\frac{2\sqrt{51}}{-17}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12\sqrt{51}}{2*-51}=\frac{0+12\sqrt{51}}{-102}
=\frac{12\sqrt{51}}{-102}
=\frac{2\sqrt{51}}{-17}
$